VLSM subnetting question
VLSM subnetting question
Hello, I understand you're trying to grasp VLSM and subnetting concepts. To split the 172.16.0.0/24 network into four subnets using VLSM, you'd allocate 24 addresses per subnet (since 2^4 = 16 + 8 = 24). This would give you 3 subnets with 256, 128, and 64 IP addresses each. For router interfaces and sub-interfaces, assign the appropriate subnet masks like 255.255.255.0 for a standard subnet or 255.255.255.192 for a VLAN. Let me know if you need further clarification!
Hi Jim,
It isn't clear how many hosts each subnet needs. Based on your reply, you likely want to pick an IP address from the assigned range for the routers. Would you like guidance on selecting a valid address within that range?
Indeed, use one from the range, just do not use the broadcast address. Great answer btw!
You can assign any address for your router, PCs, etc. Often I use a /16 subnet and leave gaps between them to boost the number of hosts later on. This aids in several ways: enhances network performance and speed, cuts down congestion, strengthens security, gives you more control over growth, and simplifies management.
@Jim79 Clarify the method for obtaining four subnets. Keep in mind that 2 raised to a power equals the number of subnets needed. In the example 172.16.0.0/24, there are 24 bits for subnetting, which gives 8 host bits. Before examining the network, think about the binary format: 11111111.1111111.11111111. For four networks you need to reduce two host bits. This means taking two host bits from the original and converting them into a /26 mask. The result is 172.16.0.0, 172.16.0.64, 172.16.0.128, and 172.16.0.192. Understanding this process makes subnetting easier. Always view it broadly first, focusing on the structure rather than the specifics until the end. Simply adjust the subnet mask for each network you define.
Hey everyone, thanks for all your responses—it really made a difference. I might have a few more questions, but for now, thanks again!