How to calculate the broadcast address?
How to calculate the broadcast address?
we understand that the subnet mask is /28, indicating 28 active bits out of 32, which translates to a binary pattern of all ones in the last block. each bit corresponds to a value from 0 to 128, and when you sum them up, it equals 255. this helps determine the number of IP addresses available within that subnet. there are two ways to calculate the possible network range based on this information.
The origin of the numbers seems related to binary encoding and masking techniques. When considering a mask value, shifting or interpreting it correctly determines the bits involved. The reference points suggest a pattern where values are derived from specific bit positions, possibly for addressing or segmentation purposes. The examples provided help clarify how ranges are calculated based on bit counts.
It uses the last value of 1 for calculation. In this example, the final block shows 10000000, so we reference the 1 with a value of 128 (8-bit). The range is based on the subnet mask, which defines the network size.
I sense you're trying to find quick solutions that occasionally succeed, but often fail. This can lead to confusion. The network address refers to the location where all host bits are zero. The broadcast address is where all host bits become one. It doesn't depend on a specific octet; it's typically in the fourth octet, though not always. There isn't a dedicated "address octet." You mentioned uncertainty about what you mean by "all 0" and always getting 255—this seems like another of those shortcuts that don’t consistently work. I’m not sure how you meant it, but if you need to calculate network, host ranges, or broadcasts, writing everything in binary (IP and subnet mask) makes it easier. Then adjust the host bits to zero for the network address and all ones for the broadcast address. Let's use question 3 as an example. I assume it asks whether a host can have the IP 43.187.105.124 with a /28 subnet. First, convert the IP to binary. The subnet mask defines which bits go to the network and which to the host. By setting the network portion to zero and the host portion to all ones, we can determine the valid range. In this case, the network address comes out as 43.187.105.112, and the broadcast address is 43.187.105.127. The usable host range spans from 43.187.105.113 to 43.187.105.126. Since 43.187.105.124 falls within this range, it is a valid host address. Subnetting can be tricky at first, but understanding the logic clarifies things. I tried to simplify it for you.
I understand the origins of the numbers. The 128 and 140 values are clear, but I need to confirm if the network updates every 128 entries.
The mask indicates /28 which equals 255.255.255.240, showing the network updates every 16 IP addresses.
I handle it another way. The IP is 164.30.125.179/28 with mask 28 in binary: 11111111.11111111.11111111.11110000. To adjust the fourth octet, shift to binary and trim the mask. The first three bytes represent networks, then from the fourth byte onward, you keep only the last four bits. This gives a broadcast address 164.30.125.10110011, which is 11 in the broadcast range, 00 for the network, and 01/10 for the host.
At the beginning, you determined this time span: 15.40.17.128 15.40.17.144. I’m not sure how this specific address group was generated. I understand network updates happen every 16.
This particular scenario means the initial three bytes identify the network, so they shouldn't affect your host range calculation. However, this isn't universal. For instance, with a /22 subnet mask, the third byte includes part of the host address. It seems there might be an error—typically it should be 0000 for network, 0001 for host, etc. But considering the remaining four bits in the last octet is important. You must examine the full octet rather than focusing on isolated bits.