F5F Stay Refreshed Power Users Networks You would divide the network by creating 14 separate subnets from 230.4.4.0.

You would divide the network by creating 14 separate subnets from 230.4.4.0.

You would divide the network by creating 14 separate subnets from 230.4.4.0.

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Draycia
Junior Member
4
07-31-2016, 09:33 PM
#1
You're trying to create 14 subnets from a given IP address. That's a bit unusual since 16 is a common size for subnets. Let's break it down. First, determine the number of bits you want to use for the subnet mask. Since you need 14 subnets, you'll need at least 4 bits (2^4 = 16), but you're aiming for 14, which suggests using a smaller range or adjusting your approach. You might consider using a 15-bit address space or modifying your requirements slightly. For guidance, clarify the host ID range, broadcast address, and new subnet mask once you decide on the configuration.
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Draycia
07-31-2016, 09:33 PM #1

You're trying to create 14 subnets from a given IP address. That's a bit unusual since 16 is a common size for subnets. Let's break it down. First, determine the number of bits you want to use for the subnet mask. Since you need 14 subnets, you'll need at least 4 bits (2^4 = 16), but you're aiming for 14, which suggests using a smaller range or adjusting your approach. You might consider using a 15-bit address space or modifying your requirements slightly. For guidance, clarify the host ID range, broadcast address, and new subnet mask once you decide on the configuration.

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ChristineD
Member
69
08-10-2016, 02:28 PM
#2
I refer to 14 subnets as ranges of IP addresses derived from the original address. You don't need to manually create each one; starting at /31 (230.4.4.0/31) and expanding upward to /16 (230.4.0.0/16) automatically generates the required segments.
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ChristineD
08-10-2016, 02:28 PM #2

I refer to 14 subnets as ranges of IP addresses derived from the original address. You don't need to manually create each one; starting at /31 (230.4.4.0/31) and expanding upward to /16 (230.4.0.0/16) automatically generates the required segments.

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yooooooomu
Member
148
08-13-2016, 11:18 PM
#3
Essentially the IP is 230.4.4.0/24. What bothers me is figuring out how to handle 14 subnets. Below is a chart I created for 16 subnets using 218.4.4.0. Network ID Subnet Mask Host ID Range # of Usable Hosts Broadcast ID 218.4.4.0 /28 218.4.4.1 - 218.4.14 14 218.4.4.15 218.4.4.16 /28 218.4.4.17 - 218.4.30 14 218.4.4.31 218.4.4.32 /28 218.4.4.33 - 218.4.46 14 218.4.4.47 218.4.4.48 /28 218.4.4.49 - 218.4.62 14 218.4.4.63 218.4.4.64 /28 218.4.4.65 - 218.4.78 14 218.4.4.79 218.4.80 /28 218.4.4.81 - 218.4.94 14 218.4.4.95 218.4.96 /28 218.4.4.97 - 218.4.110 14 218.4.4.111 218.4.4.112 /28 218.4.4.113 - 218.4.126 14 218.4.4.127 218.4.4.128 /28 218.4.4.129 - 218.4.142 14 218.4.4.143 218.4.4.144 /28 218.4.4.145 - 218.4.158 14 218.4.4.159 218.4.4.160 /28 218.4.4.161 - 218.4.174 14 218.4.4.175 218.4.4.176 /28 218.4.4.177 - 218.4.190 14 218.4.4.191 218.4.4.192 /28 218.4.4.193 - 218.4.206 14 218.4.4.207 218.4.4.208 /28 218.4.4.209 - 218.4.222 14 218.4.4.223 218.4.4.224 /28 218.4.4.225 - 218.4.238 14 218.4.4.239 218.4.4.240 /28 218.4.4.241 - 218.4.254 14 218.4.4.255
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yooooooomu
08-13-2016, 11:18 PM #3

Essentially the IP is 230.4.4.0/24. What bothers me is figuring out how to handle 14 subnets. Below is a chart I created for 16 subnets using 218.4.4.0. Network ID Subnet Mask Host ID Range # of Usable Hosts Broadcast ID 218.4.4.0 /28 218.4.4.1 - 218.4.14 14 218.4.4.15 218.4.4.16 /28 218.4.4.17 - 218.4.30 14 218.4.4.31 218.4.4.32 /28 218.4.4.33 - 218.4.46 14 218.4.4.47 218.4.4.48 /28 218.4.4.49 - 218.4.62 14 218.4.4.63 218.4.4.64 /28 218.4.4.65 - 218.4.78 14 218.4.4.79 218.4.80 /28 218.4.4.81 - 218.4.94 14 218.4.4.95 218.4.96 /28 218.4.4.97 - 218.4.110 14 218.4.4.111 218.4.4.112 /28 218.4.4.113 - 218.4.126 14 218.4.4.127 218.4.4.128 /28 218.4.4.129 - 218.4.142 14 218.4.4.143 218.4.4.144 /28 218.4.4.145 - 218.4.158 14 218.4.4.159 218.4.4.160 /28 218.4.4.161 - 218.4.174 14 218.4.4.175 218.4.4.176 /28 218.4.4.177 - 218.4.190 14 218.4.4.191 218.4.4.192 /28 218.4.4.193 - 218.4.206 14 218.4.4.207 218.4.4.208 /28 218.4.4.209 - 218.4.222 14 218.4.4.223 218.4.4.224 /28 218.4.4.225 - 218.4.238 14 218.4.4.239 218.4.4.240 /28 218.4.4.241 - 218.4.254 14 218.4.4.255

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JosephGamez
Member
141
08-15-2016, 04:20 AM
#4
I believe your terminology might be a bit unclear. 218.4.4.0 wouldn't qualify as an IP address because zero is outside the valid range, which would refer to a network address space. An actual address needs to fall within the usable range, with each part ranging from 1 to 255. Using your example, 218 represents the overall address space or the main domain. The numbers after the dot (like 4.4) are subnet addresses, similar to streets in a map. You can adjust these to create smaller network segments. The 0 in this position isn't an address—it's like a house number that you can't use. If you need 14 subnets within that space, you'd split the range accordingly.
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JosephGamez
08-15-2016, 04:20 AM #4

I believe your terminology might be a bit unclear. 218.4.4.0 wouldn't qualify as an IP address because zero is outside the valid range, which would refer to a network address space. An actual address needs to fall within the usable range, with each part ranging from 1 to 255. Using your example, 218 represents the overall address space or the main domain. The numbers after the dot (like 4.4) are subnet addresses, similar to streets in a map. You can adjust these to create smaller network segments. The 0 in this position isn't an address—it's like a house number that you can't use. If you need 14 subnets within that space, you'd split the range accordingly.

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willdoespixel
Member
208
08-16-2016, 05:13 AM
#5
You're correct that the range isn't suitable for your address. The issue is that I'm still getting familiar with networking concepts, and they provided a challenging exercise. It seems confusing because 14 subnets doesn't follow the typical pattern. For 16 subnets, you can easily determine the subnet mask by setting four bits to 1, resulting in 255.255.255.240. With 14 subnets, it appears the mask should be 255.255.255.224 or similar. I understand this might be unclear, especially since your instructor seems to be pushing a specific approach. I apologize if this causes confusion, and I appreciate you pointing out the potential mismatch with what I'm learning.
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willdoespixel
08-16-2016, 05:13 AM #5

You're correct that the range isn't suitable for your address. The issue is that I'm still getting familiar with networking concepts, and they provided a challenging exercise. It seems confusing because 14 subnets doesn't follow the typical pattern. For 16 subnets, you can easily determine the subnet mask by setting four bits to 1, resulting in 255.255.255.240. With 14 subnets, it appears the mask should be 255.255.255.224 or similar. I understand this might be unclear, especially since your instructor seems to be pushing a specific approach. I apologize if this causes confusion, and I appreciate you pointing out the potential mismatch with what I'm learning.

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BloodArsenal
Member
176
08-18-2016, 12:27 AM
#6
I think you're confusing CIDR with a netmask. Since this is a hugely complicated topic and one which I'm not exactly an expert on myself I'll link you a good article explaining how CIDR works and how it relates to netmasks. The last thing I want to do is give you incorrect info for your learning https://whatismyipaddress.com/cidr
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BloodArsenal
08-18-2016, 12:27 AM #6

I think you're confusing CIDR with a netmask. Since this is a hugely complicated topic and one which I'm not exactly an expert on myself I'll link you a good article explaining how CIDR works and how it relates to netmasks. The last thing I want to do is give you incorrect info for your learning https://whatismyipaddress.com/cidr

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137
08-21-2016, 09:22 AM
#7
I need clarification on your requirements. Please specify the subnet size, whether you want full utilization of the /24, and if all subnets must be identical. Let me know any constraints so I can assist properly.
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jedi_sandmite_
08-21-2016, 09:22 AM #7

I need clarification on your requirements. Please specify the subnet size, whether you want full utilization of the /24, and if all subnets must be identical. Let me know any constraints so I can assist properly.

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Nik_Vince
Member
137
08-22-2016, 02:48 AM
#8
In the task, we need to identify Subnet IDs, host ranges, broadcast addresses, and new subnet masks. We start with an IP address and create 14 subnets. Each subnet must accommodate an equal number of hosts. We determine the host count using 2^n - 2, where N represents the number of zeros in the last octet of the host ID. For example, with a class C address, having 4 zeros means 2^4 - 2 = 14 hosts per subnet. The goal is to fully use the network portion of the IP address, specifically the trailing zero in the .0 part. We must ensure all subnets are uniform in size and host capacity.
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Nik_Vince
08-22-2016, 02:48 AM #8

In the task, we need to identify Subnet IDs, host ranges, broadcast addresses, and new subnet masks. We start with an IP address and create 14 subnets. Each subnet must accommodate an equal number of hosts. We determine the host count using 2^n - 2, where N represents the number of zeros in the last octet of the host ID. For example, with a class C address, having 4 zeros means 2^4 - 2 = 14 hosts per subnet. The goal is to fully use the network portion of the IP address, specifically the trailing zero in the .0 part. We must ensure all subnets are uniform in size and host capacity.

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Darkshark606
Junior Member
40
08-22-2016, 09:11 AM
#9
You need to create a section for network ID, subnet mask, primary and terminal host addresses, and then the broadcast address. Your teacher refers to this process as subnetting.
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Darkshark606
08-22-2016, 09:11 AM #9

You need to create a section for network ID, subnet mask, primary and terminal host addresses, and then the broadcast address. Your teacher refers to this process as subnetting.

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MegaDisco
Senior Member
352
08-27-2016, 03:32 AM
#10
If you need to split a /24 network into 14 equal subnets, it isn't feasible. I'd request the instructor for more details.
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MegaDisco
08-27-2016, 03:32 AM #10

If you need to split a /24 network into 14 equal subnets, it isn't feasible. I'd request the instructor for more details.

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