More networking questions
More networking questions
Sure, I can help with that. For a network with the address 192.168.99.0, you’ll need a mask that creates at least four subnets. This typically involves using a mask like 255.255.255.224, which gives you 16 subnets (2^4). The new subnets would range from 192.168.99.1 to 192.168.99.15, with gateways set appropriately and destination IPs adjusted accordingly.
Examine subnet masks ranging from /25 to /32. Identify which one allows you to split a /24 network evenly into four subnets. Subnet= 192.168.99.x/yy Gateway= 192.168.99.x (start of the subnet) + 1 Broadcast= 192.168.99.x (next subnet) minus 1 Example: Creating two /25 subnets, the first would use Subnet= 192.168.99.0/25 Gateway= 192.168.99.1 Broadcast= 192.168.99.127 (as the next subnet is 192.168.99.128/25). Edit: Corrected my spelling errors
He has slight discrepancies in the numbers. The range 192.168.99.0/25 expands to 192.168.99.1 through 126, with broadcast at 127. For 192.168.99.128/25 it spans 192.168.99.129 to 254, broadcast at 255. When splitting into four subnets, use /26 and the following IPs:
- ID range: 0/64/128/192
- Broadcasts: 63, 127, 191, 255
- 192.168.99.0/26 – 192.168.99.1–62 (Broadcast 63)
- 192.168.99.64/26 – 192.168.99.65–126 (127)
- 192.168.99.128/26 – 192.168.99.129–190 (191)
- 192.168.99.192/26 – 192.168.99.193–254 (255)
The "/26" indicates a subnet mask of 255.255.255.192. The firewall gateway should point to the chosen IP within each range.